Home > Error In > Error In Complete.cases# Error In Complete.cases

## Related 1Is there a analog of complete.cases for variables in R?2Difference between complete.cases and !is.na4R: Sum Complete.cases in one column grouped by (or sorted by) a value in another column0Complete.cases used

more hot questions question feed lang-r **about us tour help blog chat** data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Max. > >>> 0.0580 0.7160 0.8270 0.7988 0.9110 1.0000 > >>>> mdl=factor(data$model) > >>>> summary(mdl) > >>> alt altPet b1 b13 b13PETalt Powered by Biostar version 2.2.0 Traffic: 226 users visited in the last hour Also if you see the example, the last 3 points are important. –user3900 Sep 3 '11 at 15:32 Your last 3 data points have null importance unless they are

I'll look into it more. + seth -- Seth Falcon | @sfalcon | http://userprimary.net/users ADD REPLY • link written 6.8 years ago by Seth Falcon • 150 On Dec 11, 2009, If one case in group "tot" is >> missing, is it possible to identify the corresponding cases in the >> other factor levels and delete them? >> >> Jim >> >> I came across the same issue, and as you pointed out, I had list objects in data.frame. –zx8754 Feb 4 '15 at 8:48 add a comment| 1 Answer 1 active oldest asked 2 years ago viewed 991 times active 1 year ago Linked 1536 How to make a great R reproducible example?

When I do, prob1[prob1$Education!=1] this doesn't make any sense, because I'm saying to subset prob1 but to do this I have to specify which rows I want and which columns I Wilcoxon in small samples4Mann-Whitney U **test and** paired data2How can a paired test less powerful than unpaired test?0Non-normal, related but non-paired data, test for significant difference0Cupcakes! How? Has she came or Did She came Which payment ID to receive XMR on an address generated with moneroaddress.org?

- This is likely related and will >> take some more looking to understand if the bug is in the IRanges method def >> or in R. >> >> > Just in
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- Though, I >>> chose to perform a pairwise.t.test what would be quite simple.

This script gives me p-value but I do not know if it is correct. It would be a pretty bad error if it did paired tests and data aren't paired/matched. No idea what is happening > pairwise.t.test(x = data$tss,data$pa,p.adjust.method = 'bonferroni',paired=TRUE) Error in complete.cases(x, y) : not all arguments have the same length > pairwise.t.test(x = data$tss,data$algo,p.adjust.method = 'bonferroni') Pairwise Of course I can check NAs in every column using sum(is.na()) funciton but I am curious why complete.cases() doesn't work.

Than... Can a character Level Up twice in a row? Find all matrices that commute with a given square matrix Can Klingons swim? Unlike SAS, R uses the same symbol for character and numeric data.

How to answer boss question about ex-employee's current employer? When i pass this data frame through the function i face the following error: Error in apply(apply(X, 2, is.na), 2, which) : error in evaluating the argument 'X' in selecting a Which Test for multiple Paired Data?0How to test group differences when elements within a group are not independent?3How to test whether matched pairs have mean difference of 0? Why are so many metros underground?

It would be a pretty bad error if it did paired > tests and data aren't paired/matched. Why isn't the Memory Charm (Obliviate) an Unforgivable Curse? Somebody needs to remove the newlines from that message. Please explain what is wrong with my proof by contradiction.

There have been some non-trivial fixes to some >> methods package code in recent R-devel. What would be a good approach to make sure my advisor goes through all the report? X contains the number or cookies for each hour before the treatment and Y contains the number of cookies after the treatment. x <- c(1,2,NA,3)

mean(x) # returns NA

mean(x, na.rm=TRUE) # returns 2 The function complete.cases() returns a logical vector indicating which cases are complete. # list rows of data

However, if I add the paired = T (pairwise.t.test(x = data$tss,data$pa,paired = T) is gives me the error ' Error in complete.cases(x, y) : not all arguments have the same Not the answer you're looking for? This post will go over some of those seemingly nonsensical errors so you don't have to go crazy trying to find the bug in your code. 1. Max. > >>> 0.0580 0.7160 0.8270 0.7988 0.9110 1.0000 > >>>> mdl=factor(data$model) > >>>> summary(mdl) > >>> alt altPet b1 b13 b13PETalt b14 b18 > >>> b7 pet pluv > >>>

I checked that na.omit works fine with your dataset so you can use it instead. I look back at my dataset and make sure that both those variables are the same length, which they are. Max. > >>> 0.0580 0.7160 0.8270 0.7988 0.9110 1.0000 > >>>> mdl=factor(data$model) > >>>> summary(mdl) > >>> alt altPet b1 b13 b13PETalt

What makes you say that? Does Detect Magic allow you to recognize the shape of a magic item? Four line equality Is masking before unsigned left shift in C/C++ too paranoid? I expect to get number of complete cases but instead I get an error saying that "not all arguments have the same legnth".

All Rights Reserved. Since one of those values is unknown, the difference will also be unknown. You chose paired test, so provide it with pairs. Asking client for discount on tickets to amusement park Does the string "...CATCAT..." appear in the DNA of Felis catus?

What I discovery now is if I run the function without paired = T (pairwise.t.test(x = data$tss,data$pa) is works. R code to accompany Real-World Machine Learning (Chapter 2) GoodReads: Machine Learning (Part 3) One Way Analysis of Variance Exercises Most visited articles of the week How to write the first more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed If you lumped the times into days instead of hours, it seems like you wouldn't have this problem anymore, and the expense of losing time specificity.

There may be some implications of this that I have not thought through. If one case in group "tot" is > >> missing, is it possible to identify the corresponding cases in the > >> other factor levels and delete them? > >> > However, > >> no > >>> matter I rearrange my response and factor vectors (as a factor or > >> numeric) > >>> it gives me the following error (the code X contains 4 values and Y contains 7 values.

As @hrbrmstr correctly pointed out, the data.frame has list objects.

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